Progress Bar in Bash

progress_bar.sh

#!/usr/bin/bash
# source: https://stackoverflow.com/questions/238073/how-to-add-a-progress-bar-to-a-shell-script/68298090#68298090
percentBar ()  { 
    local prct totlen=$((8*$2)) lastchar barstring blankstring;
    printf -v prct %.2f "$1"
    ((prct=10#${prct/.}*totlen/10000, prct%8)) &&
        printf -v lastchar '\\U258%X' $(( 16 - prct%8 )) ||
            lastchar=''
    printf -v barstring '%*s' $((prct/8)) ''
    printf -v barstring '%b' "${barstring// /\\U2588}$lastchar"
    printf -v blankstring '%*s' $(((totlen-prct)/8)) ''
    printf -v "$3" '%s%s' "$barstring" "$blankstring"
}

    ((prct=10#${prct/.}*totlen/10000, prct%8)) &&
        printf -v lastchar '\\U258%X' $(( 16 - prct%8 )) ||
            lastchar=''

I don't understand ((prct=10#${prct/.}*totlen/10000, prct%8))

Otherwise, numbers take the form [base#]n, where the optional base is a decimal number between 2 and 64 representing the arithmetic base, and n is a number in that base. If base# is omitted, then base 10 is used.

That answers the question: what does 10# mean in the expression 10#${prct/.}*totlen/10000?

https://www.gnu.org/software/bash/manual/html_node/Shell-Arithmetic.html

https://mywiki.wooledge.org/ArithmeticExpression

You may use commas to separate multiple expressions within a single math context. The final value of the arithmetic expression is that of the last comma-delimited expression.

That explains ',' between prct=10#${prct/.}*totlen/10000 and prct%8

for i in {0..10000..33} 10000;do i=0$i
    printf -v p %0.2f ${i::-2}.${i: -2}
    percentBar $p $((COLUMNS-9)) bar
    printf '\r|%s|%6.2f%%' "$bar" $p
    read -srt .002 _ && break    # console sleep avoiding fork
done

What does the underscore in read -srt .002 _ mean?