[groovy] list dirs/files (dir first and sort as name)

file_list.groovy

import groovy.io.*

def listfiles(dir) {
	dlist = []
	flist = []
	new File(dir).eachDir {dlist << it.name }
	dlist.sort()
	new File(dir).eachFile(FileType.FILES, {flist << it.name })
	flist.sort()
	return (dlist << flist).flatten()
}

fs = listfiles(".")
fs.each {
	println it
}

Well, I figured it out, and I was running it on a Linux machine.
Thanks, @herculosh for a Quick reply :)

Below is my code, Hopefully, it will useful for someone, I am running this code as a groovy script in Jenkins Pipeline

**@NonCPS
def fetFilenamesFromDir(def dir, def list){
dir.eachFileRecurse (FileType.FILES) { file ->
file = file.toString()
if (file.endsWith("json")){
list << file
}
}
}

node('master'){
def list = []

def dir = new File("dirPathToBeDefined")
fetFilenamesFromDir(dir,list)

for (i in list){
print i
print("\n")
}**