Yoni Lavi yoniLavi

Thought about cryptic crossword clues for 7m 4s:

Laying out the options I’m working through a cryptic crossword clue, analyzing synonyms, and considering anagrams and wordplay to uncover the answer.

Identifying an anagram OK, let me see. I’m thinking the cryptic clue suggests “OXTEMPTSSHARK” is an anagram. Trying different letter arrangements to find a common (1,5,3,4) phrase.

Identifying potential words I’m gathering info on the frequency of each letter. Using “A” as the starting letter, I’m considering a (1,5,3,4) phrase with available letters.

	"""
	Discrete probability distribution simulator with proper dependency tracking.

	This module implements discrete probability distributions from first principles,
	correctly handling complex dependencies between random variables.

	Examples:
	>>> die = RandomVariable.die()
	>>> coin = RandomVariable.coin()

	#include <Wire.h>
	#include <LiquidCrystal_I2C.h>

	LiquidCrystal_I2C lcd(0x27, 16, 2);

	const int trigPin = 9;
	const int echoPin = 10;
	const int ledPin = 3; // PWM pin for LED

	// Adjust these values to match your desired range

	// Potentiometer
	int potPin = A0;

	// 7-Segment Display
	const int sA = 1;
	const int sB = 7;
	const int sC = 5;
	const int sD = 4;
	const int sE = 3;
	const int sF = 2;

	import pulp
	import pandas as pd


	warehouses = pd.Series({"Dublin": 300, "Cork": 200, "Galway": 200})
	targets = pd.Series({"Belfast": 150, "Limerick": 250, "Sligo": 200})
	costs = pd.DataFrame({
	"Belfast": [16, 14, 13],
	"Limerick": [18, 12, 15],
	"Sligo": [11, 13, 17]

	from controller import Robot, DistanceSensor, Motor

	TIME_STEP = 64
	SPEED = 3.14
	PROXIMITY_THRESHOLD = 80

	robot = Robot()

	def setup_sensor(device_id):
	sensor = robot.getDevice(f"ps{device_id}")

	from sympy import symbols, Eq, laplace_transform
	from sympy.physics.mechanics import dynamicsymbols

	t, s, G, F = symbols('t s G F')
	g, f = dynamicsymbols('g f') # type: ignore

	# Equation: d^2g/dt^2 + 4dg/dt + 3g = 0.2 df/dt + 1.5f
	eq_lhs = g.diff(t, t) + 4 * g.diff(t) + 3 * g # type: ignore
	eq_rhs = 0.2 * f.diff(t) + 1.5 * f # type: ignore

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