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-module(test). | |
-compile(export_all). | |
%% API | |
run_all_sorted_sublist(List, Num) -> | |
lists:sublist(lists:sort( | |
fun({_,A,_},{_,B,_}) -> A > B end, | |
List), Num). | |
run_gb_trees(List, Num) -> | |
run_gb_trees(List, Num, gb_trees:empty()). | |
run_gb_trees([], _Num, Acc) -> | |
lists:foldl(fun({Key1, Key2, Key3}, Sum) -> [{Key2, Key1, Key3}|Sum] end, [], gb_trees:keys(Acc)); | |
run_gb_trees([{Key1, Key2, Key3}|List], Num, Acc) -> | |
NewKey = {Key2, Key1, Key3}, | |
NewAcc = | |
case gb_trees:size(Acc) < Num of | |
true -> | |
gb_trees:insert(NewKey, 0, Acc); | |
false -> | |
{Smallest,_} = gb_trees:smallest(Acc), | |
case Smallest < NewKey of | |
true -> | |
Acc2 = gb_trees:delete(Smallest, Acc), | |
gb_trees:insert(NewKey, 0, Acc2); | |
false -> | |
Acc | |
end | |
end, | |
run_gb_trees(List, Num, NewAcc). | |
run_small_to_big_order_list(List, Num) -> | |
run_small_to_big_order_list(List, Num, 0, []). | |
run_small_to_big_order_list([], _Num, _, Acc) -> | |
lists:foldl(fun({Key1, Key2, Key3}, Sum) -> [{Key2, Key1, Key3}|Sum] end, [], Acc); | |
run_small_to_big_order_list([{Key1, Key2, Key3}|List], Num, Len, Acc) -> | |
NewKey = {Key2, Key1, Key3}, | |
{NewLen, NewAcc} = | |
case Len < Num of | |
true -> | |
{Len + 1, lists:sort([NewKey|Acc])}; | |
false -> | |
[Smallest|Acc2] = Acc, | |
case Smallest < NewKey of | |
true -> | |
{Len, lists:sort([NewKey|Acc2])}; | |
false -> | |
{Len, Acc} | |
end | |
end, | |
run_small_to_big_order_list(List, Num, NewLen, NewAcc). | |
run_small_to_big_order_list_v2(List, Num) -> | |
run_small_to_big_order_list_v2(List, Num, fun({_, X, _}, {_, Y, _}) -> X =< Y end, 0, []). | |
run_small_to_big_order_list_v2([], _, _, _, Acc) -> | |
lists:reverse(Acc); | |
run_small_to_big_order_list_v2([NewKey|List], Num, Fun, Len, Acc) -> | |
{NewLen, NewAcc} = | |
if Len < Num -> {Len + 1, insert(NewKey, Acc, Fun)}; | |
true -> | |
[Smallest|Acc2] = Acc, | |
case Fun(Smallest,NewKey) of | |
true -> {Len, insert(NewKey, Acc2, Fun)}; | |
false -> {Len, Acc} | |
end | |
end, | |
run_small_to_big_order_list_v2(List, Num, Fun, NewLen, NewAcc). | |
insert(K, [], _) -> [K]; | |
insert(K, [H|T], Fun) -> | |
case Fun(K, H) of | |
true -> [K, H|T]; | |
false -> [H|insert(K, T, Fun)] | |
end. | |
run_big_to_small_order_list(List, Num) -> | |
run_big_to_small_order_list(List, Num, 0, []). | |
run_big_to_small_order_list([], _Num, _, Acc) -> | |
Acc; | |
run_big_to_small_order_list([Key|List], Num, Len, Acc) -> | |
{NewLen, NewAcc} = | |
case Len < Num of | |
true -> | |
{Len + 1, lists:sort(fun({_X1, Y1, _Z1},{_X2, Y2, _Z2}) -> Y1 > Y2 end, [Key|Acc])}; | |
false -> | |
Smallest = lists:last(Acc), | |
case Smallest < Key of | |
true -> | |
Acc2 = lists:sublist(Acc, Len - 1), | |
{Len, lists:sort(fun({_X1, Y1, _Z1},{_X2, Y2, _Z2}) -> Y1 > Y2 end, [Key|Acc2])}; | |
false -> | |
{Len, Acc} | |
end | |
end, | |
run_big_to_small_order_list(List, Num, NewLen, NewAcc). | |
test() -> | |
List1 = [{5000, 20}, {5000, 30}, {5000, 40}, {5000, 50}, {5000, 60}, {5000, 70}], | |
List2 = [{10000, 20}, {10000, 30}, {10000, 40}, {10000, 50}, {10000, 60}, {10000, 70}], | |
List3 = [{15000, 20}, {15000, 30}, {15000, 40}, {15000, 50}, {15000, 60}, {15000, 70}], | |
List4 = [{20000, 20}, {20000, 30}, {20000, 40}, {20000, 50}, {20000, 60}, {20000, 70}], | |
List5 = [{25000, 20}, {25000, 30}, {25000, 40}, {25000, 50}, {25000, 60}, {25000, 70}], | |
Result1 = lists:map(fun({TotalNum1, TopNum1}) -> test(TotalNum1, TopNum1) end, List1), | |
Result2 = lists:map(fun({TotalNum2, TopNum2}) -> test(TotalNum2, TopNum2) end, List2), | |
Result3 = lists:map(fun({TotalNum3, TopNum3}) -> test(TotalNum3, TopNum3) end, List3), | |
Result4 = lists:map(fun({TotalNum4, TopNum4}) -> test(TotalNum4, TopNum4) end, List4), | |
Result5 = lists:map(fun({TotalNum5, TopNum5}) -> test(TotalNum5, TopNum5) end, List5), | |
io:format("~p~n", [Result1]), | |
io:format("~p~n", [Result2]), | |
io:format("~p~n", [Result3]), | |
io:format("~p~n", [Result4]), | |
io:format("~p~n", [Result5]), | |
ok. | |
%% Test | |
test(TotalNum, TopNum) -> | |
erlang:process_flag(trap_exit, true), | |
List = prepared_random_list(TotalNum), | |
%io:format("~p~n", [List]), | |
Fun1 = fun() -> {Time, Result} = timer:tc(?MODULE, run_all_sorted_sublist, [List, TopNum]), exit({all_sorted_sublist_____, Time, Result}) end, | |
Fun2 = fun() -> {Time, Result} = timer:tc(?MODULE, run_gb_trees, [List, TopNum]), exit({gb_tree________________, Time, Result}) end, | |
Fun3 = fun() -> {Time, Result} = timer:tc(?MODULE, run_small_to_big_order_list, [List, TopNum]), exit({small_to_big_order_list, Time, Result}) end, | |
Fun4 = fun() -> {Time, Result} = timer:tc(?MODULE, run_big_to_small_order_list, [List, TopNum]), exit({big_to_small_order_list, Time, Result}) end, | |
Fun5 = fun() -> {Time, Result} = timer:tc(?MODULE, run_small_to_big_order_list_v2, [List, TopNum]), exit({small_to_big_order_list_v2, Time, Result}) end, | |
spawn_link(Fun1), | |
spawn_link(Fun2), | |
spawn_link(Fun3), | |
spawn_link(Fun4), | |
spawn_link(Fun5), | |
{Type1, Time1, Res1} = receive {'EXIT', _Pid1, R1} -> R1 end, | |
{Type2, Time2, Res2} = receive {'EXIT', _Pid2, R2} -> R2 end, | |
{Type3, Time3, Res3} = receive {'EXIT', _Pid3, R3} -> R3 end, | |
{Type4, Time4, Res4} = receive {'EXIT', _Pid4, R4} -> R4 end, | |
{Type5, Time5, Res5} = receive {'EXIT', _Pid5, R5} -> R5 end, | |
Res1 = Res2 = Res3 = Res4 = Res5, | |
{{TotalNum, TopNum}, [{Type1, Time1, 100}, | |
{Type2, Time2, Time2/Time1*100}, | |
{Type3, Time3, Time3/Time1*100}, | |
{Type4, Time4, Time4/Time1*100}, | |
{Type5, Time5, Time5/Time1*100}]}. | |
prepared_random_list(TotalNum) -> | |
List = lists:seq(1,TotalNum), | |
List1 = shuffle(List), | |
lists:map(fun(Num) -> {Num, Num+1, Num+3} end, List1). | |
% Fisher-Yates shuffle | |
shuffle(List) -> shuffle(List, []). | |
shuffle([], Acc) -> Acc; | |
shuffle(List, Acc) -> | |
{Leading, [H | T]} = lists:split(random:uniform(length(List)) - 1, List), | |
shuffle(Leading ++ T, [H | Acc]). | |
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The benchmark is flawed in a way that runs test concurrently. It means they interfere with themselves. For example, if some of them use more operations which make more work and use less reduction it will have an unfair advantage over other in this benchmark.