Created
April 24, 2012 20:36
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Different solutions for Fizz Buzz in Ruby
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| def fizz_buzz_1(max) | |
| arr = [] | |
| (1..max).each do |n| | |
| if ((n % 3 == 0) && (n % 5 == 0)) | |
| arr << "FizzBuzz" | |
| elsif (n % 3 == 0) | |
| arr << "Fizz" | |
| elsif (n % 5 == 0) | |
| arr << "Buzz" | |
| else | |
| arr << n | |
| end | |
| end | |
| return arr | |
| end | |
| def fizz_buzz_2(max) | |
| arr = [] | |
| (1..max).each do |n| | |
| if (n % 3 == 0) | |
| if (n % 5 == 0) | |
| arr << "FizzBuzz" | |
| else | |
| arr << "Fizz" | |
| end | |
| elsif (n % 5 == 0) | |
| arr << "Buzz" | |
| else | |
| arr << n | |
| end | |
| end | |
| return arr | |
| end | |
| def fizz_buzz_3(max) | |
| arr = [] | |
| (1..max).each do |n| | |
| text = "" | |
| if (n % 3 == 0) | |
| text << "Fizz" | |
| end | |
| if (n % 5 == 0) | |
| text << "Buzz" | |
| end | |
| if !((n % 3 == 0) || (n % 5 == 0)) | |
| text = n | |
| end | |
| arr << text | |
| end | |
| return arr | |
| end |
Aketzu
commented
Feb 13, 2018
@willwright82 's solution modified for less == 0:
(1..100).map do |m|
case 0
when m % 15 then 'FizzBuzz'
when m % 3 then 'Fizz'
when m % 5 then 'Buzz'
else m
end
enddef fizzbuzz(int)
if int % 3 == 0 && int % 5 == 0
"FizzBuzz"
elsif int % 3 == 0
"Fizz"
elsif int % 5 == 0
"Buzz"
else int % 4 == 0
nil
end
end
70 characters
(1..100).map{|x|puts x%15==0?'FizzBuzz':x%5==0?'Buzz':x%3==0?'Fizz':x}
When I thought we already had way too many solutions... !
module BeingMultiple
refine Integer do
def eitherFizzOrBuzz!
return "FizzBuzz" if multiple?(3) && multiple?(5)
return "Fizz" if multiple?(3)
return "Buzz" if multiple?(5)
self
end
private
def multiple?(target)
self % target == 0
end
end
end
using BeingMultiple
puts (1..n).map(&:eitherFizzOrBuzz!).join("\n")require "fizzbuzz"
RSpec.describe FizzBuzz do
describe "#compute" do
context "when number is dvisisble by 3" do
it "returns fizz" do
expect(FizzBuzz.compute(6)).to eq("fizz")
end
end
context "when number is dvisisble by 5" do
it "returns buzz" do
expect(FizzBuzz.compute(10)).to eq("buzz")
end
end
context "when number is dvisisble by both 3 and 5" do
it "returns buzz" do
expect(FizzBuzz.compute(15)).to eq("fizzbuzz")
end
end
end
end
class FizzBuzz
def self.compute(number)
return "fizzbuzz" if (number % 15).zero?
if (number % 3).zero? "fizz" else "buzz" end
end
endfor n in 1..101
print "Fizz" if n%3 == 0
print "Buzz" if n%5 == 0
print n unless n%3 == 0 || n%5 == 0
print "\n"
end(1..100).each_with_object([]) do |number, array|
next array << "FizzBuzz" if number % 15 == 0
next array << "Fizz" if number % 3 == 0
next array << "Buzz" if number % 5 == 0
array << number
end
Author
Fizz Buzz, Object-Oriented Edition
module NumericRefinements
refine Numeric do
def divisible_by?(other) = remainder(other).zero?
end
endclass Replacement
def self.for(n) = @registered.find { it.valid? n }.new(n).to_s
def initialize(n) = @n = n
def self.valid?(n) = false
def to_s = self.class.name
private
# Subclasses defined later take precedence
def self.register(subclass) = (@registered ||= []).prepend subclass
def self.inherited(subclass) = register subclass
endusing NumericRefinements
class TheNumber < Replacement
def self.valid?(n) = true
def to_s = @n.to_s
end
class Fizz < Replacement
def self.valid?(n) = n.divisible_by?(3)
end
class Buzz < Replacement
def self.valid?(n) = n.divisible_by?(5)
end
class FizzBuzz < Replacement
def self.valid?(n) = Fizz.valid?(n) && Buzz.valid?(n)
endclass Game
def initialize(limit: 16) = @limit = limit
def to_a = (1..@limit).collect { Replacement.for it }
end
puts Game.new.to_a
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